Author Topic: Generating the PFCC from memory  (Read 108 times)

Khepri

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Generating the PFCC from memory
« on: July 23, 2022, 07:51:23 am »
This is a new thread to discuss the idea brought up in the Published TROM thread.

Jur93n mentioned a method to recall and draw out PFCC.

From my own perspective this is a valuable datum, having a personal connection to the data so that this chart may be presented at will. The basic TROM data should be sufficient to generate this.

I begin with the 4 Legs and each of their Game Conditions, Self is on the Left and Not-Self is on the Right.

Leg 1 - MBK - MNK
Leg 2 - MNBK - MK
Leg 3 - MK - MNBK
Leg 4 - MNK - MBK

Each of these have two conditions - one where Self initiates and the other where Not-Self initiates the game. In both of these the SD and PD postulates of both parties are extant.

At this point then eight of the rows can be populated - in my revised chart the Origin/Receipt of the Game is shown by an arrow.

Thus :

Leg 1
MBK -> MNK
MBK <- MNK

Leg 2
MNBK -> MK
MNBK <- MK

Leg 3
MK -> MNBK
MK <- MNBK

Leg 4
MNK -> MBK
MNK <- MBK

From either one of these scenarios there are another two states - one where Self is overwhelmed (Motivator) or the other where Not-Self is overwhemed (Overt). When Self commits the Overt we remain where we are so that is positioned at the 'stronger' end of the Leg, where Self is overwhelmed that is positioned closer to the next Leg as that is where we will come back in. The arrow in these circumstances determines the flow of the Overt, opposed to the initiator of the Game in the previous rows.

Thus:

Leg 1
MBK -> MK (Overt)
MBK -> MNK
MBK <- MNK
MNBK <- MNK (Motivator)

Leg 2
MNBK -> MNK (Overt)
MNBK -> MK
MNBK <- MK
MBK <- MK (Motivator)

Leg 3
MK -> MBK (Overt)
MK -> MNBK
MK <- MNBK
MNK <- MNBK (Motivator)

Leg 4
MNK -> MNBK (Overt)
MNK -> MBK
MNK <- MBK
MK <- MBK (Motivator)

In the Overwhelm states there is no PD postuate for the Receiving party - they have succumbed and 'Cannot Help But' (MUST) the imposed Postulate.

« Last Edit: July 23, 2022, 09:47:22 am by Khepri »

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Jur93n

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Re: Generating the PFCC from memory
« Reply #1 on: July 23, 2022, 10:07:28 pm »
Ok now so there are a couple of things that we need:
- Two wide columns, one for Self and one for Not Self
- Each wide column is split into Origin and Receipt

We know that:
- First postulate was a Must Be Known postulate
- Time-Track runs from bottom to top

Then Not-Self/Origin from top to bottom can be filled in by going round the package and each leg starts with Overt followed by Game:
- Must Be Known (Overt)
- Must Be Known (Game)
- 2 empty rows
- Mustn't Be Known (Overt)
- Mustn't Be Known (Game)
- 2 empty rows
- Mustn't Know (Overt)
- Mustn't Know (Game)
- 2 empty rows
- Must Know (Overt)
- Must Know (Game)
- 2 empty rows

The Self/Origin is the upside-down version of what we just filled in at Not-Self/Origin.

Overts are complementary postulates, Games are opposing postulates, so now we can easily fill in the receipt points.

Note: You can add 'Motivator' to Self/Receipt where Not-Self/Origin is an Overt.

Done
« Last Edit: July 23, 2022, 10:16:35 pm by Jur93n »
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